Question

What is this ? I don’t know

Answer 1

The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced three times. Write the voltage in exponential form. What was the original voltage in the circuit?

Answer:

The exponential form of voltage
`x^(3) =(27)/(125)`

The original voltage in the circuit
`x=(3)/(5)`

Explanation:

Let
`x` be the original voltage.

Given.

Three times reduced voltage is
`(27)/(125)`

And it is multiplied by itself each time when it is reduced, this gives us

`x* x* x=x^(3)`

So the exponential form of voltage is

`x^(3) = (27)/(125)`

Solve this equation for original voltage.

`x^(3) = (27)/(125)`

`x = ((27)/(125))^{(1)/(3)}`

`x=\frac{\sqrt[3]{27} }{\sqrt[3]{125} }`

`x=\frac{\sqrt[3]{3*3*3}}{\sqrt[5]{5*5*5}}`

`x=(3)/(5)`

And Original voltage is
`x=(3)/(5)`