Answer:
![\$18,330](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lrskdsj3q57mkqmpf69t2ovu8mtp3qnkwn.png)
Explanation:
1) Usually, the areas of farms, properties, etc. are quadrilateral forms. Since these legs are not congruent and there's one leg missing then the farmland consists of a trapezoid. Finding out the northern border.
![[tex]BD^(2)=AD^(2)+AB^(2)\Rightarrow BD=\sqrt{7597.7^(2)+10468^(2)}\Rightarrow BD=\pm 12,934.60 \: ft\\BD^(2)=BC^(2)+CD^(2)\Rightarrow 12934.60^(2)=7428.9^(2)+CD^(2)\Rightarrow CD=10588.45](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cl8nsgedho8ngldkg1f5p6mndpchwghc94.png)
2)Tracing a line segment connecting BD, and since AD ⊥ BD we have two right triangles. So now let's calculate the hypotenuse and subsequently, the northern leg of this trapezoid, to finally calculate the area. Notice that, we flipped the figure and took the southern border as the height.
![\\S\:farmland=(1)/(2)(7597.7+7428.9)10468\Rightarrow S=78659224.4 ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j1qvqspwzygxr0xof9lbwjv3gyi1eplaj2.png)
3) Finally, converting from square feet to a square mile. Knowing that 1 square foot is equal to 3.59 square mile. And multiplying the converted outcome in square miles by $6500 the cost for the farmer is $18,330.
![1 square\:feet = 3.59\:square\:mile\:S =2.82\:mi^(2)\\If \: 1 \:mi^(^2)=\$6,500\:\:then \:3.59\:mi^(2)\:=\$18,330](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ynajipmycoxl58tjoooov1lkkxvxl072tn.png)