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How many moles are contained in 3.131 × 1024 particles?

User Rmalouf
by
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1 Answer

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Answer:

There are 5.199 moles in
3.131* 10^(24) particles.

Step-by-step explanation:


N=n* N_A

Where:

N = Number of particles / atoms/ molecules

n = Number of moles


N_A=6.022* 10^(23) mol^(-1) = Avogadro's number

We have:

N =
3.131* 10^(24)

n =?


n=(N)/(N_A)=(3.131* 10^(24))/(6.022* 10^(23) mol^(-1))

n = 5.199 moles

There are 5.199 moles in
3.131* 10^(24) particles.

User Rcubefather
by
5.5k points