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56% of US adults have very little confidence in newspapers. You randomly select 10 US adults. Find the probability that the number of US adults who have very little confidence in newspapers is (a) exactly five, (b) at

least six, and (c) less than four

(a) P(5)=

(Round to three decimal places as needed)

Answer 1

0.229, 0.530, 0.091

Explanation:

given that 56% of US adults have very little confidence in newspapers.

You randomly select 10 US adults.

X, the no of US adults in the sample of 10 adults who have very little confidence in newspapers is

Binomial since there are only two outcomes and each adult is independent of the other

X is bin (10, 0.56)

a) P(X=5) =0.229

b)
`P(X\geq 6) = 0.5304\\`=0.530

c)
`P(X<4) = 0.0908\\=0.091`