Question

Circle M is shown. Line segments J L and H K are diameters that intersect at center point M. Angle K M L is 25 degrees.

What is the approximate length of minor arc JH? Round to the nearest tenth of a centimeter.

Answer 1

3.5 cm

Explanation:

Answer 2

Arc(JH) = 0.44r

Explanation:

In this question radius of the circle is not given.

Given information: Line segments J L and H K are diameters that intersect at center point M, m∠KML = 25°.

Using given information draw a diagram as shown below.

From the below figure it is clear that ∠KML and ∠JMH are vertically opposite angles.

If two lines intersect each other then vertically opposite angles are equal.

`m\angle KML=n\angle JMH=25^(circ)`

Let the radius of the circle M is r.

The formula for arc length is

`s=2\pi r((\theta)/(360))`

where, r is radius of the circle and θ in degree.

`Acr(JH)=2\pi r((25)/(360))`

`Acr(JH)=0.436332313r`

`Acr(JH)\approx 0.44r`

Note: If the value of r is given, then substitute the value of r in the above equation and round to the nearest tenth of a centimeter.

Therefore, the length of arc (JH) is 0.44r.