Question

What is the volume of a 0.0355mol/L calcium hydroxide solution required to react completely with 50.0mL of 0.250mol/L aluminum sulfate solution

Answer 1

V₁ = 0.35 L

Step-by-step explanation:

Given data:

Molarity of calcium hydroxide = 0.0355 M

Volume of aluminium sulfate = 50.0 mL ( 50/1000 = 0.05 L)

Molarity of aluminium sulfate = 0.250 M

Volume of calcium hydroxide = ?

Solution:

M₁V₁ = M₂V₂

V₁ = M₂V₂ / M₁

V₁ = 0.250 M . 0.05 L / 0.0355 M

V₁ = 0.0125 M.L/ 0.0355 M

V₁ = 0.35 L