Question

A horizontal rectangular surface has dimensions 3.20 cm by 3.90 cm and is in a uniform magnetic field that is directed at an angle of 32.0 ∘ above the horizontal.Part AWhat must the magnitude of the magnetic field be to produce a flux of 3.80 ×10−4 Wb through the surface?Express your answer with the appropriate units.

Answer 1

`B =0.574\ T`

Step-by-step explanation:

given,

dimension of rectangular surface = 3.20 cm x 3.90 cm

angle of magnetic field above horizontal = 32°

θ = 90° - 32° = 58°

flux = Ф = 3.80 ×10⁻⁴ Wb

Magnetic filed = ?

`\phi=\int B.ds`

`\phi= B.ds cos \theta`

`B =(\phi)/(ds cos \theta)`

`B =(3.8 * 10^(-4))/(3.20 * 3.9 * 10^(-4)cos 58^0)`

`B =0.574\ T`

The magnetic field produced is equal to
`B =0.574\ T`