Answer:
Diane has a booth at the state fair that sells bags of popcorn she has found that her daily costs are approximated by the function c(x) =x squared -20x+150
a) How many bags of popcorn must Diane sell to minimize her cost?
b) What is Diane’s minimum cost?
a) 10
b) 50
Explanation:
According to the quadratic equation given in the question ,
![C(X)=x^(2) -20x+150](https://img.qammunity.org/2020/formulas/mathematics/high-school/e601p4ln30c74cegm1vfuadzxhve7aapbb.png)
the cost will be minimum at
![x= -(b)/(2a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zfolpqku3ildn00vfuqk70jqyrazkxt8aj.png)
comparing x^{2} -20x+150[/tex] with the standard quadratic equation
![ax^(2) +bx^(2) +c](https://img.qammunity.org/2020/formulas/mathematics/high-school/i8iebvfd516fhydcebo0ywlijk1aqb8z6z.png)
we get
a= 1, b = -20, c=150
now
![x=-((-20))/(2(1)) \\x= 10](https://img.qammunity.org/2020/formulas/mathematics/high-school/37qoz6b67omf0yp4rqwsl590higx8lumml.png)
Hence to minimize her cost, she must sell
a) x= 10 popcorns
and her minimum cost is
b)
![C(10)= (10)^(2) -20(10)+150\\C(10) = 100-200+150\\C(10) = 50](https://img.qammunity.org/2020/formulas/mathematics/high-school/ayayqrn9la3wu7ii5jrvmdktyaaj7ej7jw.png)