Question

How many grams of KOH are present in 29.5 mL of a 6.82 V KOH solution?​

Answer 1

Mass of KOH = 11.48 g

Step-by-step explanation:

Given data:

Molarity of KOH = 6.82 M

Volume = 29.5 mL (0.03 L)

Mass of KOH = ?

Solution:

Number of moles = molarity × volume

Number of moles = 6.82 M × 0.03 L

Number of moles = 0.205 mol

Mass:

Mass of KOH = number of moles × molar mass

Mass of KOH = 0.205 mol × 56 g/mol

Mass of KOH = 11.48 g