The question is missing the table and equation. So, I have attached the same below.
Answer:
Coyote is faster than a roadrunner.
Explanation:
In order to find which animal runs faster, we have to calculate their speeds and then compare them.
Speed of a body is nothing but the slope of the graph of distance traveled and time taken as speed is the ratio of distance and time.
Now, from the table, the slope is given as:
![m_1=(y_2-y_1)/(x_2-x_1)\\Where\ x_1.y_1,x_2,y_2\ \textrm{are two consecutive x and y values in the table}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9wjmllcivu1nxtmp26tjeupd097ne0nqel.png)
Plug in
. This gives,
![m_1=(58-29)/(2-1)=29\ ft/s](https://img.qammunity.org/2020/formulas/mathematics/middle-school/505e73v3jpy7nia7yn7v55mdzbksjkrcje.png)
Therefore, speed of roadrunner is 29 ft/s.
Now, from the equation of a coyote, the slope is determined from the coefficient of 'x'. The equation is:
![y=0.7x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6j0naqsf3i1oj0wwwtiu7hk27p1pqznwgp.png)
This equation is of the form
where, 'm' is the slope of the line.
Thus, speed of a coyote is 0.7 mi/min.
Now, in order to compare the two speeds, we need to make them in same units. Converting the speed of a coyote in ft/s gives:
1 mile = 5280 ft
∴ 0.7 miles =
![0.7* 5280=3696\ ft](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e1p06ub88423ir1slsn61opbxz6n1obwhf.png)
1 min = 60 s
Therefore, 0.7 mi/min =
![(3696)/(60)=61.6\ ft/s](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y216t49qhyx6qr4rtl4tdghqcq95sl2oha.png)
Now, speed of roadrunner is 29 ft/s and that of a coyote is 61.6 ft/s
As 61.6 is greater than 29, a coyote is faster than a roadrunner.