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Help please!!!!!!!!!

Help please!!!!!!!!!-example-1
User Adel
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1 Answer

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13 votes

Answer:

(a) 3.5

(b) x = 4

(c) -¹/₂

(d) -¹/₂

Explanation:

Part (a)

f(1) is the value of y when x = 1.

To find the value of y from a given value of x, find the position of x on the x-axis, then trace vertically until you meet the line. Once you meet the line, trace horizontally to the y-axis to find the corresponding value of y.

Therefore, f(1) = 3.5.

Part (b)

To solve f(x) = 2, find the value of x when y = 2.

To find the value of x from a given value of y, find the position of y on the y-axis, then trace horizontally until you meet the line. Once you meet the line, trace vertically to the x-axis to find the corresponding value of x.

Therefore, the solution of f(x) = 2 is x = 4.

Part (c)

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:


(f(b)-f(a))/(b-a)

Given interval: 2 ≤ x ≤ 4

Therefore:

  • a = 2
  • b = 4


\implies (f(4)-f(2))/(4-2)=(2-3)/(4-2)=-(1)/(2)

Part (d)

The average rate of change between any interval of the given function will be the same as the graph is linear. Therefore, the average rate of change from 0 to 8 is the same as the rate found in part (c): -¹/₂.

Proof

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:


(f(b)-f(a))/(b-a)

Given interval: 0 ≤ x ≤ 8

Therefore:

  • a = 0
  • b = 8


\implies (f(8)-f(0))/(8-0)=(0-4)/(8-0)=-(4)/(8)=-(1)/(2)

User Dsign
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