Question

If a sample of gas has a volume of 100.0ml when the pressure is 50.0kPa, what is volume when the pressure is increased to 400.0kPa, assuming temperature and number of moles is held constant?

Answer 1

V₂ = 12.5 mL

Step-by-step explanation:

Given data:

Initial volume = 100.0 mL

Initial pressure = 50.0 KPa

Final volume = ?

Final pressure = 400.0 KPa

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

50.0 KPa × 100.0 mL = 400 KPa × V₂

V₂ = 5000 KPa.mL/ 400 KPa

V₂ = 12.5 mL