Answer
given,
installed electric lamp = 2000
average life = 1000 hrs
standard deviation = 200 hrs
a)
let after p hors 10% bulb fails ,
P(X<p) = 0.10

from Normal distribution table,
P(Z<-1.28) = 0.10
on comparing


x = -1.28 x 200 + 1000
x = 744 hours
b) P( 900 < X < 1300) =
=

= P(-0.5 < Z < 1 .5)
= P(Z<1.5) - P(Z<-0.5)
= 0.93319 - 030854
= 0.62465
lamps may be expected to fail between 900 and 1300
= 0.62465*2000
= 1249.3
= 1249 (approx)