Question

The sum of two 5 digit numbers ABC10 + ABC12= 123422. What is A + B + C?

Answer 1

14

Explanation:

We are given that

Sum of two digit numbers=123422

The two digits numbers are ABC10+ABC12.

Let five digit number of the form =10000A+1000B+100C+10D+E

According to question

`10000A+1000B+100C+10+0+10000A+1000B+100C+10+2=123422`

`20000A+2000B+200C+20+2=120000+3000+400+20+2`

Comparing on both sides

C+C should be 14 to obtained 4.Then, carries 1

2C=14

`C=(14)/(2)=7`

2B+1 =3

B+B should not give anything carry as that it will make A to satisfy the addition.

2B=3-1=2

`B=(2)/(2)=1`

2A=12

`A=(12)/(2)=6`

Therefore, the five digit numbers are 61710 and 61712

Sum =61710+61712=123422

A+B+C=6+1+7=14

Hence , A+B+C=14