Question

To penetrate armor, a projectile's point concentrates force in a small area, creating a stress large enough that the armor fails. A species of jellyfish launches a pointed needle that can penetrate the hard shell of a crustacean. The rapid deceleration on impact creates a 32 μN force on the tip, which has a very small 15 nm radius.

Answer 1

4.527×10^{10} N/m^2

Step-by-step explanation:

Assuming that the resulting stress is asked in the question in N/m^2

The stress is given by the expression

σ = F/A

F= 32μN and A, Area= πr^2

r, radius = 15 nm

Putting values we get

`\sigma = (32*10^(-6))/(\pi* (15*10^(-9))^2)`

= 4.527×10^{10} N/m^2

hence the resulting stress is 4.527×10^{10} N/m^2