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On a game show, a contestant spins a wheel. The angular speed of the wheel was radians per second. If the wheel maintained this rate, what would be the rotation in revolutions per minute?

1 Answer

2 votes

Answer:9.54 rev/min

Step-by-step explanation:

Given

angular speed
\omega =1 rad/s

Wheel maintained at 1 rad/s

and
\omega =(2\pi N)/(60)

where N=revolution Per minute


1\cdot 60=2\pi N


N=(60)/(2\pi )


N=9.54 rev/min

User Evan Siroky
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