Question

Write the standard form of the equation of the circle with its center at (-2,0), and a radius of 10.

Answer 1

The standard form of the equation of the circle with its center at (-2,0), and a radius of 10 is
`(x+2)^(2)+y^(2)=100`

Solution:

We have been given the center of a circle and radius which are (-2,0) and 10 respectively

To find: Standard form of the equation of the circle

The standard form for the equation of a circle is given as:

`(x-a)^(2)+(y-b)^(2)=r^(2)`

Where (a, b) are the coordinate of the centre of circle and r is the radius

Now on substituting values we get,

`\begin{array}{l}{(x-(-2))^(2)+(y-0)^(2)=10^(2)} \\\\ {(x+2)^(2)+y^(2)=100} \\\\ {(x+2)^(2)+y^(2)=100}\end{array}`

So, the required standard equation of circle is :-

`(x+2)^(2)+y^(2)=100`