Question

Cedric and doug each had an equal amount of money. After cedric spent $35 and doug spent $28, the ratio of cedrics money to dougs money was 2:3. How much money did each boy habe at first?

Answer 1

Each of them had $49 at first.

Explanation:

Given:

Cedric and Doug each had an equal amount of money.

Let the number of money they had at first be x

Cedric spent = $35

Doug spent = $28

Cedric Money left =
`x-35`

Doug Money left =
`x-28`

the ratio of Cedric money to Doug money was 2:3

Hence the expression can be made as;

`(x-35)/(x-28)=(2)/(3)`

Now by cross multiplication method we get;

`3(x-35)=2(x-28)`

Now we will use distributive property to elaborate the same;

`3x-105=2x-56`

Combining common terms we get;

`3x-2x=105-56`

Using Subtraction property we get;

`x= 49`

Hence $49 they each had at first.