Answer: True
Explanation: When the alkene is being treated with Br2 in a aprotic solvent, the Br2 will get add on the alkene forming the bromonium ion. This intermediate can be formed from either of the side depending on the substituents of the alkene.
Thus, the two bromonium ions are formed in equal amounts. The alkene is acting as the elctrophile and the Br2 will act as the nucelophile as its antibonding orbital is higher in energy.