Answer:
Cyclist A
Explanation:
given,
velocity of Bicyclist A = 17 mil/hr
acceleration = 32 miles/hr²
velocity of Bicyclist B = 20 miles/hr
acceleration = 2 miles/hr²
which cyclist in front after = 15 minutes = 1/4 hour
using equation of motion for cyclist A
![s = ut +(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/college/mr5ktpv1516e3gt3jqv1fpph82mrhkb2xx.png)
![s = 17 * (1)/(4) +(1)/(2)* 32 * 0.25^2](https://img.qammunity.org/2020/formulas/mathematics/college/6xiv5g77m05yg4nh8umgk3bj03reiksenh.png)
s = 5.25 mile
using equation of motion for cyclist B
![s = ut +(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/college/mr5ktpv1516e3gt3jqv1fpph82mrhkb2xx.png)
![s = 20* (1)/(4) +(1)/(2)* 2 * 0.25^2](https://img.qammunity.org/2020/formulas/mathematics/college/o84284iq0j1gfxhgh52a1stnnhvnqzdvnl.png)
s = 5.0625 mile
Cyclist A will be in-front after 15 minutes