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What is the equation of a line with points -3,-11 and 2,4?​

User Trena
by
7.8k points

1 Answer

3 votes

Answer:

y=3x-2

Explanation:


(4-(-11))/(2-(-3)) =(15)/(5) =3

m=3 so using point-slope intercept form


y-y_(1)=m(x-x_(1) )

y-4=3(x-2)

3x-6

+4 +4

y=3x-2

User Mbit
by
8.1k points

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