Question

Un recipiente está lleno de un líquido cuya densidad es 1,18 g/cm3. Se introducen en él un trozo de cobre de peso específico 8,9 g/cm3, uno de ladrillo con peso específico 1,18 g/cm3, unos mililitros de nafta de densidad 0,7 g/cm3 y por último una astilla de mármol de peso específico 2,8 g/cm3. Dibuje un esquema del recipiente y ubique los cuerpos y el líquido, justificando dicha ubicación. (El líquido no reacciona químicamente con ninguno de los agregados).

Answer 1

see explanation below

Step-by-step explanation:

I'm gonna answer in english, because it's the requirement to do so.

First, density and specific weight are relationated. When you have distint liquids and solid, and you put them together in one vessel, you can predict the position of each of them, just watching their values of density and specific weight.

Always, but always, liquids with higher density goes to the bottom of the vessel. This explains why some objects or body floats in water. Suppose you have an object with an specific weight of 0.8 g/cm3 and you put it in water which it's density is 1 g/cm3. As water has a greater density, the object will not sink and sumerge into water; instead, it's going to float over water.

Same principle applies here. If the object has a higher density than the medium, the object will go to the bottom.

So, the positions for each of the objects and liquids here are the following (The number indicates the position from up to down):

1. Nafta (0.7)

2. brick (1.18)

3. liquid (1.18)

4. mármol (2.8)

5. copper (8.9)

The drawing that you need is on the picture, and the explanation is above.