Question

Water flows straight down from an open faucet. The cross-sectional area of the faucet is 1.00 × 10 − 4 m², and the speed of the water is 0.72 m/s as it leaves the faucet. Ignoring air resistance, find the cross-sectional area of the water stream at a point 0.19 m below the faucet.

Answer 1

Answer:
`A_2=0.349* 10^(-4) m^2`

Explanation:

Given

velocity
`v_1=0.72 m/s`

Area of cross-section
`A_1=1* 10^(-4) m^2`

velocity after Falling 0.19 m

`v_2^2-v_1^2=2g\cdot h`

`v_2^2=v_1^2+2g\cdot h`

`v_2^2=(0.72)^2+2* 9.8* 0.19`

`v_2^2=0.518+3.724`

`v_2=√(4.24)`

`v_2=2.05 m/s`

conserving Flow

`A_1v_1=A_2v_2`

`1* 10^(-4)* 0.72=A_2* 2.05`

`A_2=0.349* 10^(-4) m^2`