Answer:
Choose the first alternative

Explanation:
Probabilities
The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions
and the total number of possible choices
, i.e.

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total
We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.
To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

The total number of possible choices is

The probability is then

Choose the first alternative