Question

Calculate the morality for the following
10.5 kg of Na2 SO4. 10H2O in 18.60 L

Answer 1

1.75M

Step-by-step explanation:

The problem deals with finding the molarity of the given compound.

The compound is:

Na₂SO₄.10H₂O

Mass of the compound = 10.5kg = 10500g

Volume of the compound = 18.6L

Molarity is the number of moles of solute in a solution;

Molarity =
`(number of moles )/(volume)`

Number of moles =
`(mass)/(molar mass)`

Molar mass of Na₂SO₄.10H₂O = 2(23) + 32 + 4(16) + 10[2(1) + 16]

= 322g/mol

Now;

Number of moles =
`(10500)/(322)` = 32.6mole

So;

Molarity =
`(32.6)/(18.6)` = 1.75M