Answer:
A. 1/6
Step-by-step explanation:
A male fly trisomic for chromosome 4 with genotype +/+/ey is crossed with a normal, diploid eyeless female. i.e
δ +/+/ey ey/ey ⊕
+, +, +/+, ey, +/ey, +/ey × ey/ey
ey/+, +/ey, +/+/ey, ey/ey, +/ey/ey, +/ey/ey
ey/+, +/ey, +/+/ey, ey/ey, +/ey/ey, +/ey/ey
=2/12
=1/6