Question

WILL GIVE BRAILYEST TO WHOEVER ANSWERS CORRECTLY FIRST: On a coordinate plane, a line is drawn from point C to point D. Point C is at (negative 1, 4) and point D is at (2, 0). Point C has the coordinates (–1, 4) and point D has the coordinates (2, 0). What is the distance between points C and D? d = StartRoot (x 2 minus x 1) squared + (v 2 minus v 1) squared EndRoot units

Answer 1

The distance between C and D is 5 units

Explanation:

Answer 2

Answer: 5

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Work Shown:

point C = (x1,y1) = (-1,4)

point D = (x2,y2) = (2,0)

Distance Formula

`d = \sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

`d = √((2-(-1))^2+(0-4)^2)`

`d = √((2+1)^2+(0-4)^2)`

`d = √((3)^2+(-4)^2)`

`d = √(9+16)`

`d = √(25)`

`d = 5`

The distance between point C and point D is 5 units

This is equivalent to saying that segment CD is 5 units long.