Question

Write a program that continually prompts the user for an integer input until input is entered that is less than 0. Each input that is accepted is appended to an array named inputs, until an invalid input is given. When the first invalid input is entered the program prints the array and exists.

Answer 1

Following are the program in the C++ Programming Language:

#include <iostream>//header file

using namespace std;//namespane

//set main method

int main() {

int a[100]; //set integer type array variable

int value, i = 0; //set integer variables

cout<<"Enter less than 0 to exit:"<<endl; //message for exit

cout<<"Enter the integer numbers:"<<endl; //message to enter numbers

do{ //set do while

cin>>value; //get input from the user

a[i++] = value; //append elements in array

}while(value>=0);

i--;

cout<<"\\Array are:"<<endl;//message for array

for(int k = 0;k<i;k++){ //set for loop

cout<<a[k]<<" "; //print array

}

return 0;

}

Output:

Enter less than 0 to exit:

Enter the integer numbers:

1

2

3

4

5

-1

Array are:

1 2 3 4 5

Step-by-step explanation:

Here, we set the integer data type main method "main()" and inside it:

• we set integer type array variable with index value 100.
• we set two integer type variable "value" and "i" initialize value 0.
• we set the do-while loop in which we get the input from the user and and append in the array and pass condition if the value is greater then equal to 0.
• Finally, set for loop and print the elements of an array.