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A ball on a string is swung at a constant speed of 3m/s in a horizontal circle.if the string is 1.25m long what is the centripetal acceleration of the ball?

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Answer:

The centripetal acceleration of the ball swung at constant speed is, a = 7.2 m/s²

Step-by-step explanation:

Given data,

The speed of the ball, v = 3 m/s

The length of the string, r = 1.25 m

The centripetal acceleration of the ball swung at constant speed is given by the formula,

a = v²/ r

= 3² / 1.25

= 7.2 m/s²

Hence, the centripetal acceleration of the ball swung at constant speed is, a = 7.2 m/s²

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