Question

The graph of f(x) = 24x^2 + 63x +34/ 4x + 3 has an oblique asymptote at y =

a. x + 1.
b. 4x + 3.
c. 6x + 11.
d. 63x + 34.

Answer 1

Answer:C

Explanation:

Answer 2

Correct answer is C). 6X+11

Explanation:

The given function f(x)=
`(24x^(2) +63x + 34 )/(4x+3)`

On simplying the function f(x),

f(x)=
`(6x(4x+3) -18x +63x + 34 )/(4x+3)`

f(x)=
`(6x(4x+3) +45x + 34)/(4x+3)`

f(x)=
`(6x(4x+3) +11(4x+3)+x-33 + 34 )/(4x+3)`

f(x)=
`(6x(4x+3) +11(4x+3)+x+1)/(4x+3)`

f(x)=
`(6x+11)+((x+1))/(4x+3)`

From above equation

"(6x+11)" is Oblique asymptote and
`((x+1))/(4x+3)` is vertical asymptote

Therefore, Correct answer is C). 6X+11