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he physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 59 and a standard deviation of 7. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 52 and 59?

User Latlio
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1 Answer

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Answer: 34%

Explanation:

Given : The distribution of the number of daily requests is bell-shaped and has a mean of 59 and a standard deviation of 7.

i.e.
\mu=59 and
\sigma=7

According to the 68-95-99.7 rule, about 68% of the population lies in one standard deviation from the mean.

About 34% of the population lies one standard deviation above the mean and About 34% of the population lies one standard deviation below the mean.

For the given situation, 34% of lightbulb replacement requests lies one standard deviation below the mean .

i.e.About 34% of lightbulb replacement requests lies between
\mu-\sigma and
\mu .

i.e. About 34% of lightbulb replacement requests lies between
59-7 and
59 .

i.e. About 34% of lightbulb replacement requests lies between
52 and
59 .

Hence, the approximate percentage of lightbulb replacement requests numbering between 52 and 59 = 34%

User Vishal Gupta
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