Answer:

Explanation:
Remember that three points are collinears if they stay in the same line.
To find the line that pass through A(-2,3) and A''(3,7), we find first the slope of the line and then the y-intercept.
The slope of the line is

The y-intercept of the line is

Then the equation of the line is

Since we want that the point A'(x,y) stay in the line, then we need to choose a value for x and replace in the equation found.
If we take x=2

Then the points
are collinear.