Question

How many grams are there in a 29 grams of a 0.285M solution of 385ml

Answer 1

Answer: 266.055 g

Step-by-step explanation:

We have the following data related to this unknown substance:

`grams-of-substance=29 g` are the grams of substance

`molarity=0.285M` is the molarity of the substance, given by the following formula:

`molarity=(moles-of-solute)/(Volume-of-solution-in-liters)` (1)

In this case the volume of solution is
`385 ml (1L)/(1000 mL)=0.385 L`

Finding the moles of solute:

`moles-of-solute=(0.285M)(0.385 L)` (2)

`moles-of-solute=0.109 moles` (3)

Now we have to convert this to grams by the following relation:

`(grams-of-substance)/(moles-of-substance)=(molar-mass-substance-in-grams)/(1 mole)` (4)

Finding
`molar-mass-substance-in-grams`:

`molar-mass-substance-in-grams=(grams-of-substance)/(moles-of-substance) 1 mole` (5)

`molar-mass-substance-in-grams=(29 g)/(0.109) 1 mole` (6)

`molar-mass-substance-in-grams=266.05 g`