Question

29.0g silver combine completely with 4.30g of sulfur to form a compound. what is the percent composition of this compound?

Answer 1

Percentage of silver and sulphur in the compound is 87.08% and 12.91% respectively

Step-by-step explanation:

Given:

Amount of silver = 29.0 g

Amount of sulphur= 4.30 g

To find:

Percent composition of the compound=?

Solution:

`\text { percent of compound }=\frac{\text { amount of element }}{\text { Total Molecule Mass }} * 100`

Total Molecule mass = amount of silver + amount of sulphur

Total Molecule mass = 29+4.3

Total Molecule mass = 33.3g

Percentage of silver:

`\text { Percentage of silver }=\frac{\text { amount of silver }}{\text { Total Molecule Mass }} * 100`

=>
`(29.0)/(33.3)*100`

=>
`0.8708 *100`

=> 87.08%

Percentage of silver:

`\text { Percentage of silver }=\frac{\text {amount of suplhur}}{\text { Total Molecule Mass }} * 100`

=>
`(4.30)/(33.3)* 100`

=>
`0.1291* 100`

=> 12.91%