Answer:
1. 4(2x-3)(3x+7)
2. 4(9x-10)(x+1)
3. (3a+1)(3a-1)
Explanation:
1. Add and subtract the second term to the expression and factor by grouping.
2. Same thing for #2 (look at #1)
3. Since both terms are perfect squares, factor using the difference of squares formula a^(2)-b^(2)=(a+b)(a-b) where a = 3a and b = 1