Question

Calculate the acceleration due to gravity

at a height of 300 km from the surface of
the Earth. (M = 5.98 x10²4 kg, R = 6400
km).​

Answer 1

8.8854 m/s²

Step-by-step explanation:

Using the relation :

g = GM / (r + R)^2

G = Gravitational constant = 6.67 * 10^-11

M = mass of earth = 5.98 * 10^24 kg

r = distance = 300 km

R = Radius of earth 6400 km

g = (6.67 * 10^-11 * 5.98 * 10^24) / ((6400+300) * 10^3)^2

g = (6.67 * 5.98 * 10^(-11 + 24)) / (6700 * 10^3)^2

g = (39.8866 * 10^13) / 44890000 * 10^6

g = 0.000000888540 * 10^(13 - 6)

g = 0.000000888540 * 10^7

g = 8.8854 m/s²