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In 2005 a planet was found revolving about a distant sunlike star in 4.01 days. The radius of its orbit is 2 comma 600 comma 000 mi. What is its linear velocity​ (in mi/h) about its​ star?

User Bitinerant
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1 Answer

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Answer: linear velocity = 169,745.2mi/hr

Step-by-step explanation:

Given: radius of orbit= 2,600,000mi

Time taken for orbit = 4.01 days = 4.01 × 24 hrs= 96.24hrs

Linear velocity = distance travelled/time

distance travelled = circumference of orbit = 2πr

= 2π × 2,600,000mi

= 16336281.8mi

Linear velocity = 16336281.8/ 96.24hrs

= 169745.2mi/hr

User Mokk
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