Question

The diffusion constant for oxygen diffusing through tissue is 1.0 × 10-11 m2/s. In a certain sample oxygen flows through the tissue at 2.0 × 10-6 kg/s. If the thickness of the tissue is doubled, then what is the rate of oxygen flow through the tissue?

Answer 1

m' = 1 x 10⁻⁶ kg/s

Step-by-step explanation:

Given that

Diffussion constant = 1 x 10⁻¹¹

Mass flow rate ,m = 2 x 10⁻⁶ kg/s

The diffusion is inversely proportional to the thickness of the membrane and therefore when the thickness is doubled, the mass flow rate would become half.

So new flow rate m'

`m'=(m)/(2)`

`m'=(2* 10^(-6))/(2)\ kg/s`

m' = 1 x 10⁻⁶ kg/s