Question

A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels in this time​

Answer 1

Step-by-step explanation:

Consider the kinematic equation,

`x = vt + (1)/(2) a {t}^(2)`

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

`x = 3(1.8) + (1)/(2) (9.3) {1.8}^(2)`

through simple algebra we get

`x = 20.466`

where this is the distance traveled in meters.