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2. A package with a heat sink and fan has a thermal resistance to the ambient of 8 °C/W. The thermal resistance from the die to the package is 2 °C/W. If the package is in a chassis that will never exceed 50 °C and the maximum acceptable die temperature is 110 °C, how much power can the chip dissipate?

User Dscarr
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1 Answer

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To solve this problem it is necessary to apply the concepts related to the Power depending on the temperature and the heat transferred.

By definition the power can be expressed as


P = (\Delta T)/(\Delta Q)

Where,


\Delta T = T_m - T_a = Change at the temperature, i.e, the maximum acceptable die temperature (
T_m) with the allowable temperature in chassis (
T_A)


\Delta Q = Q_A-Q_D = Change in the thermal resistance to ambient (
Q_A) and the Thermal resistance from die to package (
Q_D)

Our values are given as,


T_m=110\°C


T_a= 50\°C


Q_A= 8\°C/W


Q_D= 2\°C/W

Replacing we have,


P = (110-50)/(8-2)


P = 10W

The power that can dissipate the chip is 10W

User Pranjay Kaparuwan
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