Question

In a double-slit interference experiment, a special lamp emitting yellow light from heated sodium atoms is used to produce an interference pattern on a screen located 1.49 m from a pair of slits separated by 0.12 mm. If the distance between adjacent bright regions in the resulting pattern is 7.32 mm, what is the wavelength (in nm) of the sodium light?

Answer 1

λ=589nm

Step-by-step explanation:

The wavelength of the sodium light can be calculated using the next equation:

`\lambda = (\Lambda D)/(L)`

where Λ: is the distance between the adjacent bright regions, λ: is the wavelength of the sodium light, L: is the distance between slits and screen, and D: is the distance between slits.

`\lambda = (7.32mm \cdot 0.12mm)/(1490mm) = 5.89\cdot 10^(-4)mm = 589nm`

Therefore, the λ of the sodium light is 589 nm.

I hope it helps you!