Question

About once every 30 minutes, a geyser known as Old Faceful projects water 11.0 m straight up into the air. Use g = 9.80 m/s^2, and take atmospheric pressure to be 101.3 kPa. The density of water is 1000 kg/m^3. What is the speed of the water when it emerges from the ground?

Answer 1

The speed of the water is 14.68 m/s.

Step-by-step explanation:

Given that,

Time = 30 minutes

Distance = 11.0 m

Pressure = 101.3 kPa

Density of water = 1000 kg/m³

We need to calculate the speed of the water

Using equation of motion

`v^2=u^2+2gs`

Where, u = speed of water

g = acceleration due to gravity

h = height

Put the value into the formula

`0=u^2-2*9.8*11.0`

`u=√(2*9.8*11.0)`

`u=14.68\ m/s`

Hence, The speed of the water is 14.68 m/s.