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About Here are two relations defined on the set {a, b, c, d}: S = { (a, b), (a, c), (c, d), (c, a) } R = { (b, c), (c, b), (a, d), (d, b) } Write each relation as a set of ordered pairs. (a) S ο R (b) R ο S (c) S ο S

User Jaromir
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Answer with Step-by-step explanation:

We are given that a set {a,b,c,d}

S={(a,b),(a,c),(c,d),(c,a)}

R={(b,c),(c,b),(a,d),(d,b)]

Composition of relation:Let R and S are two relations on the given set

If ordered pair (a,b) belongs to relation R and (b,c) belongs to S .

Then, SoR={(a,c)}

By using this rule

SoR={(b,d),(b,a)}[/tex]

Because
(b,c)\in R and
(c,d)\in S.Thus,
(b,d)\in SoR


(b,c))\in R and
(c,a)\in S.Thus,
(b,a)\in SoR

b.RoS={(a,c),(a,b),(c,b),(c,d)}

Because


(a,b)\in S,(b,c)\in R .Therefore, the ordered pair
(a,c)\in RoS


(a,c)\in S,(c,b)\in R .Thus,
(a,b)\in RoS


(c,d)\in S,(d,b)\in R.Thus,
(c,b)\in RoS


(c,a)\in S,(a,d)\in R.Thus,
(c,d)\in RoS

c.SoS={(a,d),(a,a),(c,c),(c,b)}

Because


(a,c)\;and\; (c,d)\in S.Thus,
(a,d)\in SoS


(c,a),(a,b)\in S.Thus,
(c,b)\in SoS


(a,c)\in S and
(c,a)\in S.Thus,
(a,a)\in SoS


(c,a)\in S and
(a,c)\in S.Thus ,
(c,c)\in SoS

User Ianna
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