Question

A car is travelling at a speed of 21m/s. It accelerates at an average rate of 3m/s^2 for a time

of 4 seconds. Find the distance it travels.​

Answer 1

S = 108m

Step-by-step explanation:

According to Second Law of Motion:

S = Vi*t + 0.5*a*t^2

Vi = 21m/s

a = 3m/s^2

t = 4s

Putting all values in Equation

S = 21*4 + 0.5*3*4^2

S = 84 + 24

S = 108m