Answer:
The probability that a student chosen at random is fluent in English or Swahili.
P(S∪E) = 1.1
Explanation:
Step(i):-
Given total number of students n(T) = 150
Given 125 of them are fluent in Swahili
Let 'S' be the event of fluent in Swahili language
n(S) = 125
The probability that the fluent in Swahili language
![P(S) = (n(S))/(n(T)) = (125)/(150) = 0.8333](https://img.qammunity.org/2022/formulas/mathematics/high-school/uavtfx79d13jnpbdpcsoilov4his6mv6vn.png)
Let 'E' be the event of fluent in English language
n(E) = 135
The probability that the fluent in English language
![P(E) = (n(E))/(n(T)) = (135)/(150) = 0.9](https://img.qammunity.org/2022/formulas/mathematics/high-school/wp1f56jt8mqd1qnagcqhenpirglgs1mzcl.png)
n(E∩S) = 95
The probability that the fluent in English and Swahili
![P(SnE) = (n(SnE))/(n(T)) = (95)/(150) = 0.633](https://img.qammunity.org/2022/formulas/mathematics/high-school/auwc473ya7jbwc0g0b3vtpwixolzfh2bck.png)
Step(ii):-
The probability that a student chosen at random is fluent in English or Swahili.
P(S∪E) = P(S) + P(E) - P(S∩E)
= 0.833+0.9-0.633
= 1.1
Final answer:-
The probability that a student chosen at random is fluent in English or Swahili.
P(S∪E) = 1.1