Answer:
[H3O+] = 0.0117 M
[OH-] = 8.5 * 10^-13 M
Step-by-step explanation:
Step 1: Data given
Concentration of HCl = 0.0117 M
Step 2:
HCl is a strong acid
pH of a strong acid = -log[H+] = - log[H3O+]
[H3O+] = 0.0117 M
pH = -log(0.0117)
pH = 1.93
pOH =14 - 1.93 = 12.07
pOH = -log[OH+] = 12.07
[OH-] = 10^-12.07 = 8.5 * 10^-13
Or
Kw / [H3O+] = [ OH-]
10^-14 / 0.0117 = 8.5*10^-13