Question

The wooden block is removed from the water bath and placed in an unknown liquid. In this liquid, only one-third of the wooden block is submerged. Is the unknown liquid more or less dense than water?

Answer 1

1.5 g/cm^3

Step-by-step explanation:

In the question i am assuming that wooden block of weight W floats with exactly one-half of its volume below the waterline.

Let ρ_{liquid} be the density of the unknown liquid , V= volume submerged

g= acceleration due to gravity

then

weight of block =
`\rho_(water)* V* g/2`

when the block is in water

Also,

weight of block =
`\rho_(liquid)* V* g/3`

dividing eq 1 by eq 2 we get

`\rho_(liquid) = 3/2 \rho_(water)`

⇒
`\rho_(liquid) = 3/2`