Question

A sample of carbon dioxide gas is reduced to 1/3 of its original volume while the pressure is observed to doubleplaced in a container the volume of the container is in the system did the temperature change?

Answer 1

The temperature will change and become 2/3 of its original.

Step-by-step explanation:

Using Ideal gas equation for same mole of gas as

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

Given ,

The volume of the sample gets reduced 1/3 of the original. So,

V₂ = 1/3V₁

The pressure of the sample is doubled of the original. So,

P₂ = 2P₁

Using above equation as:

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

`\frac {{P_1}* {V_1}}{T_1}=\frac {{2* P_1}* {(1)/(3)* V_1}}{T_2}`

`T_2=(2)/(3)* T_1`

The temperature will change and become 2/3 of its original.