Answer:
a) The debris was 256 feet into the air after 2 seconds of the explosion.
b)
![h(t) = -16t(t-10)](https://img.qammunity.org/2020/formulas/mathematics/high-school/xdz6rnzxgg0tvq1u61dkzokaxnn6ytmvg6.png)
Explanation:
We are given the following in the question:
Initial Velocity = 160 feet per second
![h(t) = 160t-16t^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/mzgn4qr1h9a8zcr625ospev3fkmxb9nc51.png)
The above function gives the height in feet and t is seconds after the explosion.
a) Height of the debris 2 second(s) after the explosion.
We put t = 2 in the above function
![h(2) = 160(2)-16(2)^2 = 256](https://img.qammunity.org/2020/formulas/mathematics/high-school/iq88n9qzjk9v5v67b2nw2ihxk7a1t0fsr4.png)
Thus, the debris was 256 feet into the air after 2 seconds of the explosion.
b) Factor the polynomial
![h(t) = 160t-16t^2\\= 16t(10-t)\\=-16t(t-10)](https://img.qammunity.org/2020/formulas/mathematics/high-school/odh57l2uc7n7xvtm1rqb37ze4p13lhnjvo.png)