Question

A force F~ = Fx ˆı + Fy ˆ acts on a particle that

undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 7 N, Fy = −1 N, sx = 3 m, and
sy = 3 m.
Find the work done by the force on the
particle.
Answer in units of J.

Find the angle between F~ and ~s.
Answer in units of ◦

Answer 1

18 and 35 degrees

Step-by-step explanation:

Answer 2

Answer: Work done is 18J

Step-by-step explanation:

Force F = (Fx, Fy) and Displacement S = (Sx,Sy)

Fx=7N

Fy=-1N

Sx=3m

Sy=3m

F=(7,-1)N and S=(3,3)m

Work done is calculated by taking dot product of force and displacement vector

W=F·S

W=7×3 + (-1)×3

W=21+(-3)=18J